Powers and Roots Practice Test 4

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Question : 9 of 40

Marks: +1, -0

{3√2}/{√6-√3}-{4√3}/{√6-√2}

-6/{√8+√12}=?

1
$- √3$
$√3+√ 2$
$√ 3-√ 2$

Solution:

{3√2}/{√6-√3}-{4√3}/{√6-√2}

-6/{√8+√12}

First,

{3√2}/{√6-√3} ×{√6+√3}/{√6+√3}

={3√12+3√6}/{ 6- 3}={3(√12+√6)}/3

=2√3+√6

Similearly,

{4√3}/{√6-√2}=3√2+√6

and

6/{√8+√12}=-3(√2-√3)

Putting the value we get,

=2√3+√6-3√2-

√6-(-3(√2-√3) )

=2√3-3√2+3√2-3√3

=2√3-3√3=-√3

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