Find the value of x in x/\sqrt^3{0.343}\div{x^2/\sqrt24.01}\times{7x^3}/\sqrt156.25=98 .

Powers and Roots Practice Test 4

Question : 24 of 40

Marks: +1, -0

Find the value of x in

x/√^3{0.343}÷{x^2/√24.01}×{7x^3}/√156.25=98

Solution:

x/√^3{0.343}÷{x^2/√24.01}×{7x^3}/√156.25=98

x/√^3{ 343/1000}÷{x^2/√{2401/100}}×{7x^3}/√{15625/100}=98

{10x}/7×49/{10x^2}×{70x^3}/125=98

{490x^2}/125=98

x^2=98×125/490

x^2=25

x=√25

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