Powers and Roots Practice Test 3

Question : 28 of 40

Marks: +1, -0

What is the square root of

(0.75)^3/{1-0.75}+[0.75+(0.75)^2+1]=?

Solution:

√{(0.75)^3/{1-0.75}+[0.75+(0.75)^2+1]}

=√{{(0.75)^3+({1-0.75}) [0.75+(0.75)^2+1]}/{1-0.75}}

=√{{(0.75)^3+1^3-(0.75)^3}/{1-0.75}}

=√{1/0.25}=1/0.5=2

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