Given that \sqrt1369 +\sqrt{0.0615+x} =37.25, then value of x is:

Powers and Roots Practice Test 2

Question : 29 of 40

Marks: +1, -0

Given that

√1369 +√{0.0615+x} =37.25

, then value of x is:

Solution:

√1369 +√{0.0615+x} =37.25

⇒37 +√{0.0615+x} =37.25

⇒ √{0.0615+x} =0.25

⇒ 0.0615 + x = 0.0625

⇒ x = 0.0625 - 0.0615

= 0.001 = 10^{-3}

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