Powers and Roots Practice Test 1

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Question : 29 of 40

Marks: +1, -0

If

√{2+x/196}=21/14

, then find

√{343/ x}

.

$√ 14$
$√48$
$√7$
$7√ 7$
7

Solution:

√{2+x/196}=21/14

Squaring both sides,

{2+x/196}= 441/196

392 + x = 441

x = 49

∴√{343/x}=√{343/49}=√7

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