If x * y =x^2+y^2+\sqrt^3 {xy}, then find the value of 56 * 49.

Powers and Roots Practice Test 1

Question : 23 of 40

Marks: +1, -0

x * y =x^2+y^2+√^3 {xy}

, then find the value of 56 * 49.

Solution:

56 * 49=56^2+49^2+√^3{56×49}

=3136+2401+√^3{2744}

= 5537+ 14 =5551

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