Permutations Practice Test 2

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Question : 8 of 30

Marks: +1, -0

The number of ways in which we can choose a committee from four men and six women so that the committee includes at least two men and at least twice as many women as men is:

94
126
136
None of these

Solution:

We have the following pattern:

M	W	Ways
2	4	$^4C_2 . ^6C_4=90$
2	5	$^4C_2 . ^6C_5=36$
2	6	$^4C_2 . ^6C_6=6$
3	6	$^4C_3 . ^6C_6=4$

∴ Total number of ways = 136

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