Permutations Practice Test 2

Question : 10 of 30

Marks: +1, -0

All the letters of the word EAMCET are arranged in possible ways. The number of such arrangementin which not two vowels are adjacent to each other is:

Validate

Solution:

First we place 3 consonant in 3! ways and then at four places (2 between them and 2 on sides) 3 vowels in which one vowel is repeated can be placed in

^4P_3/2!

ways.
Hence, required number

= {3!.^4P_3}/2! = 72

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