Permutations Practice Test 1

Question : 9 of 40

Marks: +1, -0

There are 10 people named a, b, c, d, e, f, g, h, i and j. We have the capacity to accommodate only 5. In how many ways can we arrange them in a line if a is must and g and h must not be included in the team of 5?

$^ 8 P_5$
$^7C_3 . (4!)$
$^ 7 P_5$
$^7C_3 . (5!)$

Validate

Solution:

Total number of people = 10
In which ‘g’ and ‘h’ must not be included and ‘a’ must be included.
So, we are left with 7 people.
So, number of ways

= ^7P_5

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