Percentage Practice Test 8 with solutions

Let the salary of Ranjit = Rs x
Pawan’s monthly salary = Rs 32,000
Raman’s salary is 30% more than Raman’s salary. So,
$=32000+\left(32000\times \frac{32}{100}\right)$
= 32,000 + 9,600 = Rs 41,600
= Raman’s salary
Two thirds of Ranjit’s monthly salary is equal to Raman’s salary.
x of $\frac{2}{3}$ = 41600
$\mathit{x}=41600\times \frac{3}{2}$ =Rs 62,400
So, the salary of Ranjit = Rs 62,400