Percentage Practice Test 8 with solutions

Minimum passing mark = 280
Let total marks be = x
Marks obtained by Hema = 264
She failed by 2 per cent.
Difference between passing marks and marks got by Hema = 280 - 264 = 16
So, x of 2% = 16
$\mathit{x}\times \frac{2}{100}=16$
$\mathit{x}=800$
Total marks = 800
So, the minimum pass percentage $=\frac{\mathrm{Passing}\mathrm{marks}}{\mathrm{Total}\mathrm{marks}}\times 100$
$=\frac{280}{800}\times 100=35$