Percentage Practice Test 4 with solutions

Number of pages in x = 120 pages
Number of pages in y = 10%, more = $120+120\times \frac{10}{100}$ = 132 pages
Number of pages in z = 10% less = $120-120\times \frac{10}{100}$ = 108 pages
Total pages in x, y, and z = 132 + 120 + 108 = 360 pages
Number of pages torn from = 5% of 120 $=5\times \frac{120}{100}$ = 6 pages
Number of pages torn form y = 10% of 132 $=\frac{10}{100}\times 132$ = 13.2 pages
Number of pages torn out by z is 15% of 108 $=\frac{15}{100}\times 108=16.2$ pages
Total number of pages torn out from x, y and z = 6 + 13.2 + 16.2 = 35.4 pages
Per cent of total pages torn out $=\frac{35.4}{360}\times 100=9.83\%$