Percentage Practice Test 4 with solutions

C’s annual salary = Rs 3,00,000
∴ C’s monthly salary = Rs 25,000
According to the question,
C’s monthly salary = $\frac{1}{2}$ of B’s monthly salary
So, 25,000 = $\frac{1}{2}$ (B’s monthly salary)
50,000 = B’s monthly salary.
Let A’s monthly salary be Rs x.
Then, 14% of x = 28% of B’s monthly salary
$\frac{14}{100}\times \mathit{x}=\frac{28}{100}\times 50,000$
$\therefore \mathit{x}=\frac{28}{100}\times 50,000\times \frac{100}{14}$ = 1,00,000
∴ A’s monthly salary is Rs 1,00,000.