Percentage Practice Test 3 with solutions

Question : 16 of 40

Marks: +1, -0

If A’s income is 20% more than that of B, by how much per cent is B’s income less than that of A?

Solution:

Let the income of B = x
Income of A = x + (x of 20%)

=x+x/5=6/5x

B’s income

=6/5x-x=x/5

Per cent of B’s income less than that of A’s income

={\B’s \Income }/{\A’s \Income}×100

={x/5}/{6/5x}×100=16 2/3

B’s Income is

16 2/3

less than A’s income.

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