Percentage Practice Test 3 with solutions

Let the price of an orange = Rs x
∴ New price $\frac{70}{100}\mathrm{of}\mathit{x}=\frac{7}{10}\mathit{x}$
According to the question,
$\frac{640}{7\mathit{x}}-\frac{64}{\mathit{x}}=16$
$\frac{640-448}{7\mathit{x}}=16$
$\mathit{x}=\frac{192}{7\times 16}=1.71$
Hence, price of half a dozen oranges = 6 × 1.71 = Rs 10.26
Thus, the reduced price of half a dozen oranges $=\frac{7}{10}\times 10.26=\mathrm{Rs}.7.18$