Partnership Practice Test 3

Number of sheep of A for 1 month
= [70 × 4 + (70 – $\frac{2}{7}$ × 70) × 3 + (70 – $\frac{2}{7}$ × 70 + $\frac{2}{5}$ × 40) × 5]
= 280 + 150 + 330 = 760
Number of sheep of B for 1 month = [50 × 4 + (50 + $\frac{2}{7}$ × 70) × 8] = 200 + 560 = 760
Number of sheep of C for 1 month = [40 × 7 + (40 – $\frac{2}{5}$ × 40) × 5] = 280 + 120 = 400
Hence, ratio of their sheep = 760 : 760 : 400 = 19 : 19 : 10
Sum of proportionals = 19 + 19 +10 = 48
1 year’s rent of the pasture ground = 16 × 12 = Rs. 192
∴ Rent to be paid by A = $\frac{19}{48}\times 192$ = Rs. 76
Rent to be paid by B = $\frac{19}{48}\times 192$ = Rs. 76
Rent to be paid by C = $\frac{10}{48}\times 192$ = Rs. 40