Number System Practice Test 6

Question : 7 of 12

Marks: +1, -0

If x is a whole number, then

x^2 (x^2 -1)

is always divisible by:

Solution:

x^2 (x^2 - 1)

By putting, x = 2, we get

2^2 (2^2 - 1) = 4 × 3 = 12

Hence,

x^2 (x^2 - 1)

is always divisible by 12.

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