Number System Practice Test 6

Question : 5 of 12

Marks: +1, -0

If the difference in the squares of two natural numbers is 29, find the sum of the squares of the numbers.

Solution:

Let the two numbers be x and y.

x^2-y^2=29

(x+y)(x-y)=29×1

x + y = 29 and (x - y) = 1
So, x = 15 and y = 14

x^2+y^2 = 15^+ 14^2

= 225 + 196 = 421.

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