If both 17^2 and 2^4 are factors of (6)^2 \times x \times (12)^1 \times (3)^6 \times (7)^2, which is the smallest possible value of x?

Number System Practice Test 4

Question : 38 of 40

Marks: +1, -0

If both

17^2

and

2^4

are factors of

(6)^2 × x × (12)^1 × (3)^6 × (7)^2

, which is the smallest possible value of x?

Solution:

(6)^2 × x × (12)^1 × (3)^6 × (7)^2

= 3^2 × 2^2 × x × 2^2

× 3 ×3^6 × 7^2

Since the number already, containing

2^4

, the possible smallest value of x is 172 = 289.

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