If a = 16 and b = 15, then what is the value of \frac{a^2+b^2+ab}{a^3-b^3}=?

Number System Practice Test 4

Question : 30 of 40

Marks: +1, -0

If a = 16 and b = 15, then what is the value of

{a^2+b^2+ab}/{a^3-b^3}=

Solution:

Given a = 16 and b = 15, then

{a^2+b^2+ab}/{a^3-b^3}

={a^2+b^2+ab}/{(a -b )(a^2+b^2+ab)}

=1/{a-b}=1/{16-15}=1

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