Mensuration Practice Test 9

Surface area of the larger cube = $6{\mathit{a}}^2$ = $6{\left(10\right)}^2$
= 600 $\mathit{c}{\mathit{m}}^2$
Volume of the larger cube = ${\left(\mathit{a}\right)}^3$ = ${\left(10\right)}^3$
= 1,000 cu cm
Volume of the smaller cube = ${\left(\mathit{a}\right)}^3$ = ${\left(2\right)}^3$
= 8 cu cm
Number of the smaller cubes = $\frac{1000}{8}$ = 125
Required ratio = 600 : 125 = 24 : 5