Mensuration Practice Test 9

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Question : 1 of 40

Marks: +1, -0

If ΔABC is similar to ΔDEF such that BC = 3 cm, EF = 4 cm and area of ΔABC = 54

cm^2

, then the area of ΔDEF is:

78 $cm^2$
96 $cm^2$
54 $cm^2$
66 $cm^2$

Solution:

Area of ΔABC = 54

cm^2

b × h = 54

cm^2

3 × h = 54
h =

{54}/3

= 18 cm

ΔABC is similar to ΔDEF
⇒

b/h : b_1/h_1

3/{18} : 4/h h

= 24 cm
Area of ΔDEF = b × h
4 × 24 = 96

cm^2

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