Mensuration Practice Test 7

Area of circle = $\mathit{\pi }{\mathit{r}}^2$
$\frac{22}{7}\times 4\times 4$ = $\frac{352}{7}\mathit{c}{\mathit{m}}^2$
Side of square
P = 4a = $2\mathit{d}\sqrt{2}$
d = 8

4a = 2.8 $\sqrt{2}$
a = $\frac{16\sqrt{2}}{4}$
a = $4\sqrt{2}$ cm.
Area of square = ${\mathit{a}}^2$ = ${\left(4\sqrt{2}\right)}^2$ = $32\mathit{c}{\mathit{m}}^2$
Area of portions between the square and the circle
$\frac{352}{7}-32$ = $\frac{352-224}{7}$ = $\frac{128}{7}$ = $18\frac{2}{7}\mathit{c}{\mathit{m}}^2$