Mensuration Practice Test 7

Surface area of the sphere = curved surface area of the right circular cylinder
Height of the cylinder = 12 cm
Radius = 6 cm
Curved surface area of the cylinder = 2 πrh
$2\times \frac{22}{7}\times 12\times 6$ = $\frac{3168}{7}$
= 452.57 $\mathit{c}{\mathit{m}}^2$
Area of the sphere = $4\mathit{\pi }{\mathit{r}}^2$
$\frac{450.57}{4}\times \frac{7}{22}$ = $\frac{3167.99}{88}$
${\mathit{r}}^2$ = 35.99
r = 5.99
r = 6 cm