Mensuration Practice Test 7

Area of the circle = $\mathit{\pi }{\mathit{r}}^2$
Circumference of the circle = 2π r
According to the statement,
$\mathit{\pi }{\mathit{r}}^2$ = 7 (2π r)
$\mathit{\pi }{\mathit{r}}^2$ = 14πr
${\mathit{r}}^2$ = 14r
r = 14
Circumference of the circle = 2πr
= $2\times \frac{22}{7}\times 14$ = 88 units.