The perimeter of a right-angled isosceles triangle is 2 + \sqrt2 cm. Then its area is:

Mensuration Practice Test 6

Question : 2 of 40

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The perimeter of a right-angled isosceles triangle is 2 +

√2

cm. Then its area is:

Solution:

Perimeter of the right-angled isosceles triangle =

2+√2

So, equal two sides = 1 cm each
Base =

√2

cm
Area of the triangle =

b/4 √{4a^2-b^2}

√2/4 √{4(1)^2-(√2)^2}

√2/4 (√{4-2})

√24 : √2

2/4

1/2 cm^2

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