Mensuration Practice Test 6

Question : 15 of 40

Marks: +1, -0

A well of radius 3.5 m is dug 16 m deep. The earth removed is spread over an area of 400

m^2

to form a platform. The height of the platform is:

Solution:

Volume of earth dug out of well =

πr^2h

{22}/7 × (3.5)^2 × 16

= 616

m^3

Height of the platform =

{\Volume}{/Area}

{616}/{400}

= 1.54 m

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