Mensuration Practice Test 6

Question : 11 of 40

Marks: +1, -0

If the radii of the circular ends of a trunched conical bucket which is 45 cm high is 28 cm and 7 cm, then the capacity of the bucket in the cubic centimeter is (use π = 22/7) its
area which is:

48,510 $cm^2$
50,600 $cm^2$
46,506 $cm^2$
61,616 $cm^2$

Validate

Solution:

Volume =

1/3 πh (R^2+Rr+r^2)

1/3 × {22}/7 × 45[(28)^2+(28×7)+(7)^2]

1/3 × {22}/7 × 45

[84 + 196 + 49]
=

1/3 × {22}/7 × 45 × 1029

= 48510

cm^3

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