Mensuration Practice Test 5

Median of an equilateral triangle is divided in the ratio 2 : 1.

So, suppose R = 2 cm
r = 1 cm.
Area of the first circle : area of the second circle
$\mathit{\pi }{\mathit{R}}^2$ = $\mathit{\pi }{\mathit{r}}^2$
$\mathit{\pi }{\left(2\right)}^2$ : $\mathit{\pi }{\left(1\right)}^2$
$4\mathit{\pi }:\mathit{\pi }$
4 : 1