Mensuration Practice Test 4

Question : 40 of 40

Marks: +1, -0

A tent is of the shape of a right circular cylinder up to a height of 3 m and then becomes a right circular cone with the maximum height of 13.5 m above the ground. If the radius of the base is 14 m, the cost of painting the inner side of the tent at the rate of Rs 2 per sq. m is:

Rs 2,050
Rs 2,060
Rs 2,068
Rs 2,080

Validate

Solution:

Slant height of the cone =

√{(14)^2+(10.5)^2}

√{196+110.25}

√{306.25}

= 17.5 m
Required area =

2πrh + πrl

= πr (2h + l)
=

{22}/7 × 14 (6+17.5)

{22}/7

× 14 × 23.5 =

10.4 cm^2

Total cost = 1,034 × 2 = Rs 2,068

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