Mensuration Practice Test 4

Volume of circular cone A = $\frac{1}{3}\mathit{\pi }{\mathit{r}}^2\mathit{h}$
Volume of circular cylinder M = $\mathit{\pi }{\mathit{r}}^2\mathit{h}$
Volume of sphere C = $\frac{4}{3}\mathit{\pi }{\mathit{r}}^2$
Let r = 3 cm
h = 6 cm.
compare these terms.
A = M = C
$\frac{1}{3}\mathit{\pi }{\mathit{r}}^2\mathit{h}$ = $\mathit{\pi }{\mathit{r}}^2\mathit{h}$ = $\frac{4}{3}\mathit{\pi }{\mathit{r}}^3$
= $\mathit{\pi }{\mathit{r}}^2\left(\frac{1}{3}\mathit{h}=\mathit{h}=\frac{4}{3}\mathit{r}\right)$
= $\frac{6}{3}$ = 6 = 4
= 2 = 6 = 4
= A = M = C
= A + C = M
= A + C − M = 0