Mensuration Practice Test 4

Radius of the cylinder = 3 cm = 30 mm
Height = 5 cm = 50 mm
Volume = $\mathit{\pi }{\mathit{r}}^2\mathit{h}$
= $\mathit{\pi }{\left(30\right)}^2\left(50\right)$
= π 45,000 $\mathit{m}{\mathit{m}}^3$
Volume of the cone = $\frac{1}{3}\mathit{\pi }{\mathit{r}}^2\mathit{h}$
Height = 1 cm = 10 mm = $\frac{1}{3}\mathit{\pi }{\left(1\right)}^{2}10$
= $\frac{10}{3}\mathit{\pi }\mathit{m}{\mathit{m}}^2$
Number of cones = $\frac{\mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cylinder}}{\mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cone}}$
= $\frac{45000\mathit{\pi }}{\frac{10}{3}\mathit{\pi }}$
= 45000 × $\frac{3}{10}$ = 13500