Mensuration Practice Test 2

Diameter of the sphere = 6 cm
Radius = 3 cm
Volume = $\frac{4}{3}\mathit{\pi }{\mathit{r}}^3$
= $\frac{4}{3}\times \frac{22}{7}\times 3\times 3\times 3$ = 113.14 $\mathit{c}{\mathit{m}}^3$
Now these volume is divided into 8 equal parts.
$\frac{113.14}{8}$ = $4.14\mathit{c}{\mathit{m}}^3$
Radius of the sphere = $\frac{4}{3}\mathit{\pi }{\mathit{r}}^3$ = 14.14
${\mathit{r}}^3$ = $14.14\times \frac{7}{22}\times \frac{3}{4}$
${\mathit{r}}^3$ = $\frac{296.99}{88}$ = 3.375
r = 1.5 m