Mensuration Practice Test 2

Diagonal of the square = 4 $\sqrt{2}$ cm
Perimeter of the square = P = 4a = 2d $\sqrt{2}$.
= 2 × 4 $\sqrt{2}\times \sqrt{2}$
Perimeter = 16 cm
Side of the square = 4a = 16
a = $\frac{16}{4}$ = 4 cm
Area of the square = 4 × 4 = 16 $\mathit{c}{\mathit{m}}^2$
Area of the second square = 32 $\mathit{c}{\mathit{m}}^2$
Side of the square =Area of the square = 4 × 4 = 16 $\mathit{c}{\mathit{m}}^2$
Area of the second square = 32 $\mathit{c}{\mathit{m}}^2$
Side of the square = $\sqrt{4\sqrt{2}\times 4\sqrt{2}}$
= $4\sqrt{2}$ cm
Diagonal of the square = $\mathit{a}\sqrt{2}$
= $4\sqrt{2}\times \sqrt{2}$
= 8 cm