Mensuration Practice Test 2

Total surface = 2 (Area of base) + Perimeter × height
608 = $2{\left(\mathrm{side}\right)}^2+4\left(\mathrm{side}\right)15$
608 = $2{\left(\mathrm{side}\right)}^2$ + 60 side
Let side = x
2 (304) = $2{\mathit{x}}^2+60\mathit{x}$
304 = ${\mathit{x}}^2+30\mathit{x}$
${\mathit{x}}^2+30\mathit{x}-304$ = 0
- 30 ± $\frac{\sqrt{{\left(30\right)}^2-4\times 1\times \left(304\right)}}{2.1}$
$\frac{-30\pm \sqrt{900+1216}}{2}$
$\frac{-30\pm \sqrt{2116}}{2}$
$\frac{-30\pm 46}{2}$
- 15 ± 23
x = 8, So, side x = 8
Volume = Area of base × height
= ${\left(8\right)}^2$ × 15
= 960 $\mathit{c}{\mathit{m}}^3$