Mensuration Practice Test 2

Question : 12 of 40

Marks: +1, -0

A circular road runs around a circular ground. If the difference between the circumferences of the outer circle and the inner circle is 66 m, the width of the road is:
(Take π = 22/7)

7 m
5.25 m
21 m
10.5 m

Validate

Solution:

(2πR_1-2πR_2)

= 66

2π(R_1-r_2)

= 66

R_1-R_2

= 66

R_1/R_2

{66}/2 × 7/{22} - {21}/2

R_1-R_2

{21}/2

= 10.5 metres

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