Mensuration Practice Test 11

Volume of a cube with edge 3 cm = ${\left(3\right)}^3$ = 27 $\mathit{c}{\mathit{m}}^3$
Volume of a cube with edge (1.5) cm = ${\left(1.5\right)}^3$
= 3.375 $\mathit{c}{\mathit{m}}^2$
Number of smaller cubes that can be cut
= $\frac{27}{3.375}$ = 8 cubes
Surface area of the bigger cube = $6{\mathit{a}}^2$ = 54 $\mathit{c}{\mathit{m}}^2$
Surface area of the smaller cubes = 8 × 6 ${\left(1.5\right)}^2$
= 108 $\mathit{c}{\mathit{m}}^2$
Percentage increase = $\frac{108-54}{54}\times 100$ = 100 %