Mensuration Practice Test 10

Side of the square = $\frac{252}{4}$ = 63 cm
Area of the square = 63 × 63 = 3,969 $\mathit{c}{\mathit{m}}^2$
Radius of the circle = $\frac{252}{2\mathit{\pi }}$ = 40.09 cm
Area of the circle = $\mathit{\pi }{\mathit{r}}^2$
= $\frac{22}{7}\times \frac{252}{2\mathit{\pi }}\times \frac{252}{2\mathit{\pi }}$ = $5051\mathit{c}{\mathit{m}}^2$
Side of an equilateral triangle = $\frac{252}{3}$ = 84 cm
Area of an equilateral triangle = $\frac{\sqrt{3}}{4}{\mathit{a}}^2$
Area = $\frac{\sqrt{3}}{4}{\left(84\right)}^2$ = 3051.72
So, the circle has the largest area.