Mensuration Practice Test 10

Question : 15 of 40

Marks: +1, -0

A metal pipe is 21 cm long and its exterior diameter is 8 cm. If the thickness of the pipe is 1 cm and the metal weights

8 g\/cm^3

, the weight of the pipe (in kg) is (Use π = 22/7).

Solution:

Required weight =

πh(R^2-r^2) × R/{1000}

kg
=

[{22}/7 × 21(4^2-3^2)] × 8/{1000}

kg
= [66 × (16 - 9)] ×

8/{1000}

kg
=

(66×7×8/{1000})

kg
= 3.696 kg

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