Mensuration Practice Test 1

Question : 31 of 40

Marks: +1, -0

The wheel of an engine turns 350 times round its axle to cover a distance of 1.76 km. The diameter of the wheel is:

Solution:

Circumference of the wheel =

{\distance}/{\turns \of \wheels}

{1.76×100000}/{350}

{176000}/{350}

= 502.85 cm
Diameter of the wheel = 2πr = 502.85
r =

{502.85×7}/{22×2}

{3519.9}/{44}

r = 79.99 cm
Diameter = 159.99 cm = 160 cm

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