Mensuration Practice Test 1

Question : 15 of 40

Marks: +1, -0

ABCD is trapezium such that AB = CD and AD || BC. AD = 5 cm, BC = 9 cm. If the area of ABCD is 35 sq. cm, then CD is:

Solution:

Area of trapezium =

1/2

(9 + 5) × h = 35
=

{14}/2

× h = 35
h = 5 cm.
By Pythagoras theorem

(CD)^2

(CM)^2 + (DM)^2

(CD)^2

(5)^2+(2)^2

CD =

√{25+4}

CD =

√{29}

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