If \log_2 = 0.3010, then find the value of \log_5 512.

Logarithms Practice Test 2

Question : 8 of 39

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\log_2 = 0.3010

, then find the value of

\log_5 512

Solution:

\log_5 512={\log512}/{\log5}

={\log2^9}/{\log(10/2)}={9\log2}/{\log10-\log2}

={9×0.3010}/{1-0.3010}≈3.876

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