If \log_8m + \log_8 1/6 = 2/ 3 ; then m is equal to:

Logarithms Practice Test 2

Question : 38 of 39

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\log_8m + \log_8 1/6 = 2/ 3

; then m is equal to:

Solution:

\log_8m + \log_8 1/6 = 2/ 3

\log_8(m ×1/6) = 2/ 3

⇒m×1/6=8^{2/3}

⇒m/6=(2^3)^{2/3}

⇒m/6=4

∴m=24

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