Logarithms Practice Test 2

Question : 35 of 39

Marks: +1, -0

The value of the real number x satisfying

\log_9 x-\log_9(x/10+1/9)=1

is:

Solution:

\log_9 x-\log_9(x/10+1/9)=1

⇒\log_9 x-\log_9({9x+10}/90)=\log_9 9

⇒{90x}/{9x+10}=9

⇒x=10

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