Logarithms Practice Test 2

Question : 3 of 39

Marks: +1, -0

Find the value of:

\log (a^3 - b^3 )

- 3ab(a - b) - 3\log(a - b)

Solution:

\log (a^3 - b^3 )

- 3ab(a - b) - 3\log(a - b)

=\log(a-b)^3-\log(a-b)^3=0

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