Logarithms Practice Test 1

Question : 28 of 40

Marks: +1, -0

Solve:

\log(2^2/3)+\log(2^4/3^2)+\log(2^6/3^3)

+... +\log(2^n/3^n)

Solution:

\log(2^2/3)+\log(2^4/3^2)+\log(2^6/3^3)

+... +\log(2^n/3^n)

=\log( {2^{n(n+1)}/{3^{{n(n+1)}/2}}})

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