Logarithms Practice Test 1

Question : 24 of 40

Marks: +1, -0

1/{\log_{xy}xyz}+1/{\log_{yz}xyz}+1/{\log_{zx}xyz}=?

Solution:

Given expression

={\log_{xyz}xy }+ {\log_{xyz} yz}+ {\log_{xyz }zx}

=\log_{xyz}(xy.yz.zx)=2\log_{xyz}(xyz)=2

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