Logarithms Practice Test 1

Question : 19 of 40

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Find the value of:

7\log1+ 3\log 2+ 4\log3 -2\log 6

Solution:

7\log1+ 3\log 2+ 4\log3 -2\log 6

= \log1^7+ \log 2^3+ \log3^4 - \log 6^2

=\log 1+\log 8+\log 81-\log 36

=\log{1×8×81}/36

=\log18

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