LCM and HCF Practice Test 5

Question : 16 of 33

Marks: +1, -0

The sum of a pair of positive integers is 336 and their HCF is 21. The number of such possible pairs is:

Solution:

Let the two numbers be 21x and 21y.
According to the statement,

21(x+y)=36

x+y=336/21=16

Number of such possible pairs is 4, i.e. (1, 15), (3, 13), (5, 11) (7, 9).

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