LCM and HCF Practice Test 4

6 = 2 × 3; 8 = 2 × 2 × 2
10 = 2 × 5; 12 = 2 × 2 × 3
It is clear that 2 occurs as prime factor maximum three times, 3 one time and 5 one time.
Hence, required L.C.M. = 2 × 2 × 2 × 3 × 5 = 120